25x^2-61x+36=0

Solution for 25x^2-61x+36=0 equation:

25x^2-61x+36=0

a = 25; b = -61; c = +36;
Δ = b2-4ac
Δ = -612-4·25·36
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-11}{2*25}=\frac{50}{50}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+11}{2*25}=\frac{72}{50}
=1+11/25
$